In this post I would like to summarize what I understand about the wave equation.
The wave equation look like this u(x,t)=Asin(kx−ωt+ϕ).
The number k is the wave vector. This confused me because it looks like a scalar to me.
Suppose time freezes, if we advance x by 2πk, we get u(x+2πk,t)=Asin(k(x+2πk)−ωt+ϕ)=Asin(kx+2π−ωt+ϕ)=Asin(kx−ωt+ϕ). Therefore, 2πk is the wave length.
Switching to the time scale, if position freeze and we advance time by 2πω. It is apparent that using the same trick we get the same value. This means 2πω is the period, ω2π is the frequency, and ω is the angular frequency, nothing special about this.
To advance one wavelength, one need one period of time. Therefore the speed of the wave is v=λT=fλ=ω2π2πk=ωk.
The wave equation look like this u(x,t)=Asin(kx−ωt+ϕ).
The number k is the wave vector. This confused me because it looks like a scalar to me.
Suppose time freezes, if we advance x by 2πk, we get u(x+2πk,t)=Asin(k(x+2πk)−ωt+ϕ)=Asin(kx+2π−ωt+ϕ)=Asin(kx−ωt+ϕ). Therefore, 2πk is the wave length.
Switching to the time scale, if position freeze and we advance time by 2πω. It is apparent that using the same trick we get the same value. This means 2πω is the period, ω2π is the frequency, and ω is the angular frequency, nothing special about this.
To advance one wavelength, one need one period of time. Therefore the speed of the wave is v=λT=fλ=ω2π2πk=ωk.
No comments:
Post a Comment