Question:
What is true about $ \hat{I} \psi_0(x) $? The operator is defined as $ \hat{I} \psi(x) = \psi(-x) $.
Solution:
$ \psi_0(x) $ is an even function, so these are correct choices:
$ \hat{I} \psi_0(x) = \psi_0(-x) $.
$ \hat{I} \psi_0(x) = \psi_0(x) $.
What is true about $ \hat{I} \psi_0(x) $? The operator is defined as $ \hat{I} \psi(x) = \psi(-x) $.
Solution:
$ \psi_0(x) $ is an even function, so these are correct choices:
$ \hat{I} \psi_0(x) = \psi_0(-x) $.
$ \hat{I} \psi_0(x) = \psi_0(x) $.
No comments:
Post a Comment