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Saturday, April 25, 2015

Exploring Quantum Physics - Week 4 Question 4

Question:

What is the wavefunction of the first excited state of the quantum harmonic oscillator, |1?

Solution:

The answer can easily be read from the Quantum Harmonic Oscillator page from Wikipedia. But since this is a blog of doing exercise, what is the point of copying the answer? Let us derive it from the ground state using the creation operator.

First, we have the ground state wavefunction ψ0(x)=(mωπ)14emωx22.

Now we apply the creation operator ˆa=mω2(ˆxiˆpmω)=mω2(xmωx).

Let's first compute the derivative:

xψ0(x)=(mωπ)14emωx22mωx

So we have the momentum term:

mωxψ0(x)=(mωπ)14emωx22x=xψ0(x)

The position term is of course also xψ0(x). Combining using the creation operator we have

ˆaψ(x)=mω2(2xψ0(x))=12ψ0(x)H1(mωx).

H1 is the physicist Hermite polynomial of order 1 which is simply H1(x)=2x.

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