Question:
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What is the coefficient N for the equation ψn(x)=Nsin(nπxL).
Solution:
We will do that by normalizing the wavefunction.
1=L∫0(Nsin(nπxL))2dx=N2L∫0sin2(nπxL)dx=N2L∫01−cos(2nπxL)2dx=N2L2N=√2L
So the answer is √2L.
... Snip ...
What is the coefficient N for the equation ψn(x)=Nsin(nπxL).
Solution:
We will do that by normalizing the wavefunction.
1=L∫0(Nsin(nπxL))2dx=N2L∫0sin2(nπxL)dx=N2L∫01−cos(2nπxL)2dx=N2L2N=√2L
So the answer is √2L.
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