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Friday, April 17, 2015

Exploring Quantum Physics - Week 3 Extra Credit Question 3

Question:

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Given ϕ(x,t)=n=1anψn(x)exp(iEnt/), what must be true?

Solution:

This is the Parseval's theorem. Since ϕ(x,t)ϕ(x,t) represents a probability, we have ϕ(x,t)ϕ(x,t)dx=1. Substitute in the definition, we have:

1=ϕ(x,t)ϕ(x,t)dx=(n=1anψn(x)exp(iEnt/))(n=1anψn(x)exp(iEnt/))dx=p=1q=1apaqexp(iEpt/)exp(iEqt/)ψp(x)ψq(x)dx=p=1q=1apaqexp(iEpt/)exp(iEqt/)ψp(x)ψq(x)dx=p=1q=1apaqexp(iEpt/)exp(iEqt/)δpq=p=1|ap|2exp(iEpt/)exp(iEpt/)=p=1|ap|2

Therefore the answer is p=1|ap|2=1.

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