The proof of that identity is a straightforward verification, so here is the code that does the job for us.
Note in particular that the Einstein summation convention in action in the left hand side as $ i $ is a repeated index.
Note in particular that the Einstein summation convention in action in the left hand side as $ i $ is a repeated index.
namespace ManagedWorkspace { using System; using System.Collections.Generic; using System.Linq; internal static class Program { static int levi(int i, int j, int k) { int c = i * 100 + j * 10 + k; switch (c) { case 123: return 1; case 231: return 1; case 312: return 1; case 132: return -1; case 213: return -1; case 321: return -1; } return 0; } static int delta(int i, int j) { return i == j ? 1 : 0; } static void Main(string[] args) { for (int j = 1; j <= 3; j++) { for (int k = 1; k <= 3; k++) { for (int s = 1; s <= 3; s++) { for (int t = 1; t <= 3; t++) { int lhs = 0; for (int i = 1; i <= 3; i++) { lhs += levi(i, j, k) * levi(i, s, t); } int rhs = delta(j, s) * delta(k, t) - delta(j, t) * delta(k, s); if (lhs != rhs) { Console.WriteLine("Error!"); } } } } } } } }
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