Question:
What is the ground state energy of a bouncing neutron under the simplified, constant gravitational field?
Solution:
Just substitute the values into the equations in the lectures to give the answer:
$ \alpha = (\frac{\hbar^2 M g^2}{2})^{1/3} = 9.64 \times 10^{-32}$
$ E = -\rho \alpha = 2.25 \times 10^{-31}$
$ T = \frac{E}{k} = 1.63 \times 10^{-8} $
So the answer is 16 nano-kelvin.
What is the ground state energy of a bouncing neutron under the simplified, constant gravitational field?
Solution:
Just substitute the values into the equations in the lectures to give the answer:
$ \alpha = (\frac{\hbar^2 M g^2}{2})^{1/3} = 9.64 \times 10^{-32}$
$ E = -\rho \alpha = 2.25 \times 10^{-31}$
$ T = \frac{E}{k} = 1.63 \times 10^{-8} $
So the answer is 16 nano-kelvin.
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