Question:
What is the ground state energy of a bouncing neutron under the simplified, constant gravitational field?
Solution:
Just substitute the values into the equations in the lectures to give the answer:
α=(ℏ2Mg22)1/3=9.64×10−32
E=−ρα=2.25×10−31
T=Ek=1.63×10−8
So the answer is 16 nano-kelvin.
What is the ground state energy of a bouncing neutron under the simplified, constant gravitational field?
Solution:
Just substitute the values into the equations in the lectures to give the answer:
α=(ℏ2Mg22)1/3=9.64×10−32
E=−ρα=2.25×10−31
T=Ek=1.63×10−8
So the answer is 16 nano-kelvin.
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