Andrew's Exercise Solutions
Sunday, January 3, 2016
UTM Ideals Varieties and Algorithm - Chapter 1 Section 3 Exercise 13
Problem:
Solution:
The direction of the normal is $ (1, 1, -1) \times (-1, 2, 1) $. The cross product is (3, 0, 3).
Therefore the solution is $ 3x + 3z = 0 $, or simply $ x + z = 0 $.
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