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Monday, February 15, 2016

UTM Ideals Varieties and Algorithm - Chapter 2 Section 1 Exercise 2

Problem:


Solution:

For part (a), we can use MATLAB to compute the reduced row echelon form quickly.

rref([[2 3 -1;1 -1 0;3 7 -2] [9;1;17]])

That gives

   1.00000   0.00000  -0.20000   2.40000
   0.00000   1.00000  -0.20000   1.40000
   0.00000   0.00000   0.00000   0.00000

which means

x0.2z=2.4
y0.2z=1.4

That give the parametrization (2.4+0.2t,1.4+0.2t,t)

For part (b), we could use MATLAB again, but it is simple so I will skip and do that manually.

It is obvious that we need two parameters, and it is easy to have x1=u and x3=v as the parameters, so the second equation gives x2=u+v.

The first equation then give u+(u+v)vx4=0, so the parametrization is (u,u+v,v,2u).

For part (c), the answer is right in front of us if we simply let x=w be the parameter, so the parametrization is simply (w,w3,w5).

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