Problem:
Solution:
This is the variety $ \mathbf{V}(x - 2, y, z + 1) \cup \mathbf{V}(x^2 - y) $. Therefore ,the answer is the single point $ (2, 0, -1) $ together with a parabola $ y = x^2 $ extended to become a surface with arbitrary value $ z $. The point is not on the surface itself so it stands out as a singular point.
Solution:
This is the variety $ \mathbf{V}(x - 2, y, z + 1) \cup \mathbf{V}(x^2 - y) $. Therefore ,the answer is the single point $ (2, 0, -1) $ together with a parabola $ y = x^2 $ extended to become a surface with arbitrary value $ z $. The point is not on the surface itself so it stands out as a singular point.
No comments:
Post a Comment