Problem:
Reconsider the fundamental theorem of calculus as expressed in (1.1.16 found in the lecture note packet). But now, integrate from t−Δt to t+Δt. Using (1.1.19), what is the new version of (1.1.20):
Solution:
We start with y(t+Δt)−y(t−Δt)=t+Δt∫−t−Δtf(t,y)dt.
Next we approximate the integral by constant and put terms around, we get
yn+1=yn−1+2Δtf(t,yn).
Reconsider the fundamental theorem of calculus as expressed in (1.1.16 found in the lecture note packet). But now, integrate from t−Δt to t+Δt. Using (1.1.19), what is the new version of (1.1.20):
Solution:
We start with y(t+Δt)−y(t−Δt)=t+Δt∫−t−Δtf(t,y)dt.
Next we approximate the integral by constant and put terms around, we get
yn+1=yn−1+2Δtf(t,yn).
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