Problem:
Question 1:
Consider the function f(t)=cos(t). What is the error bound associated with expanding the function f(t+Δt) about tusing Δt=0.1. In particular, compute the error bound when truncated at the second-derivative (keep only the first two significant-digits).
Question 2:
Consider the function f(t)=cos(t). What is the error bound associated with expanding the function f(t+Δt) about t using Δt=0.1. In particular, compute the error bound when truncated at the third-derivative (keep only the first two significant-digits).
Solution:
Consider the Taylor expansions:
For question 1:
cos(t+Δt)=cos(t)−Δtsin(t)−Δt22cos(c)
So the error bound is the maximum value of the last term, which is 0.122=0.005
For question 2:
cos(t+Δt)=cos(t)−Δtsin(t)−Δt22cos(t)+Δt36sin(c)
So the error bound is the maximum value of the last term, which is 0.136=0.00017
Question 1:
Consider the function f(t)=cos(t). What is the error bound associated with expanding the function f(t+Δt) about tusing Δt=0.1. In particular, compute the error bound when truncated at the second-derivative (keep only the first two significant-digits).
Question 2:
Consider the function f(t)=cos(t). What is the error bound associated with expanding the function f(t+Δt) about t using Δt=0.1. In particular, compute the error bound when truncated at the third-derivative (keep only the first two significant-digits).
Solution:
Consider the Taylor expansions:
For question 1:
cos(t+Δt)=cos(t)−Δtsin(t)−Δt22cos(c)
So the error bound is the maximum value of the last term, which is 0.122=0.005
For question 2:
cos(t+Δt)=cos(t)−Δtsin(t)−Δt22cos(t)+Δt36sin(c)
So the error bound is the maximum value of the last term, which is 0.136=0.00017
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