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Andrew's Exercise Solutions
Friday, December 11, 2015
UTM Ideals Varieties and Algorithm - Chapter 1 Section 3 Exercise 1
Problem:
Solution:
Take the sum of the the equations, we have:
2
x
+
3
y
−
z
=
1
z
=
2
x
+
3
y
−
1
w
=
x
+
y
+
z
−
2
=
x
+
y
+
(
2
x
+
3
y
−
1
)
+
2
=
3
x
+
4
y
+
1
Therefore the solutions are, in parameters
s
and
t
, are
(
x
y
z
w
)
=
(
s
t
2
s
+
3
t
−
1
3
s
+
4
t
+
1
)
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