online advertising
Processing math: 100%

Friday, December 11, 2015

UTM Ideals Varieties and Algorithm - Chapter 1 Section 3 Exercise 1

Problem:


Solution:

Take the sum of the the equations, we have:

2x+3yz=1z=2x+3y1w=x+y+z2=x+y+(2x+3y1)+2=3x+4y+1

Therefore the solutions are, in parameters s and t, are

(xyzw)=(st2s+3t13s+4t+1)


No comments:

Post a Comment