Problem:
Saw this poster in MIT building 38 for their course 6 (i.e. EECS) - Note the @mit email address.
Solution:
The potential at the positive terminal of the power supply is -3.001V
The potential at the negative input terminal of the operational amplifier is 0 volt because it is a differential amplifier and negative feedback will drive it to 0V
The ideal operational amplifier characteristic ensure no current will flow into the amplifier, so current flows from Vout will flow all the way back to ground at the negative terminal of the power supply, this make the two resistors simply a potential divider.
Therefore $ V_{out} $ is 6.002, that is the course number of Circuits and Electronics in MIT!
Last I learnt the operational amplifier back in my high school days at around 1999, it has been 15 years since then.
Saw this poster in MIT building 38 for their course 6 (i.e. EECS) - Note the @mit email address.
Solution:
The potential at the positive terminal of the power supply is -3.001V
The potential at the negative input terminal of the operational amplifier is 0 volt because it is a differential amplifier and negative feedback will drive it to 0V
The ideal operational amplifier characteristic ensure no current will flow into the amplifier, so current flows from Vout will flow all the way back to ground at the negative terminal of the power supply, this make the two resistors simply a potential divider.
Therefore $ V_{out} $ is 6.002, that is the course number of Circuits and Electronics in MIT!
Last I learnt the operational amplifier back in my high school days at around 1999, it has been 15 years since then.
No comments:
Post a Comment