If glucose has a reducing aldehyde group, it should re-color the Schiff reagent, therefore the answer is
Glucose does not have a reducing aldehyde group.
The carbons are numbered from top to bottom. The alcohol group attached to carbon 5 is going to attack the carbonxyl carbon C1 to form hemiacetal.
That way the ring would be a 6-member ring and I believe that has least strain.
The anomeric carbon is the carbonxyl carbon, therefore the answer is C.
Depending on whether the C5 hydroxyl group attacks the front or back of the anomeric carbon, it will yield different isomers.
Pyran is a 6 member ring and furan is a 5 member ring. The answer is the number of carbon and oxygen atom in the ring.
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